x+[x+1]+(x+2)=36

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Solution for x+[x+1]+(x+2)=36 equation:


Simplifying
x + [x + 1] + (x + 2) = 36

Reorder the terms:
x + [1 + x] + (x + 2) = 36

Remove brackets around [1 + x]
x + 1 + x + (x + 2) = 36

Reorder the terms:
x + 1 + x + (2 + x) = 36

Remove parenthesis around (2 + x)
x + 1 + x + 2 + x = 36

Reorder the terms:
1 + 2 + x + x + x = 36

Combine like terms: 1 + 2 = 3
3 + x + x + x = 36

Combine like terms: x + x = 2x
3 + 2x + x = 36

Combine like terms: 2x + x = 3x
3 + 3x = 36

Solving
3 + 3x = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3x = 36 + -3

Combine like terms: 3 + -3 = 0
0 + 3x = 36 + -3
3x = 36 + -3

Combine like terms: 36 + -3 = 33
3x = 33

Divide each side by '3'.
x = 11

Simplifying
x = 11

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